is acidity se bachao.....

Ans 1..It is A only..see B cant be the answer coz the anion formed is not resonance stabalised...so we have only 2 options left A and c..actually in case of C.. NO₂ grp is meta to it..so that will not be much aciidc..and for that hydrogen bonding case u can see the table given in NCERT..the pKa values of p-Nitrophenol and o-nitrophenol differ by 0.1 only...whereas m-nitrophenol differ by 1.something ...

Ans 2..Ortho effect - due to which COOH grp changes the plane and COO^- anion is stabalised as the ring do not donate electrons to it//bcoz it is now in different plane

Ans 3.. 2nd one is more acidic..

arre yaar....table s se value mat dekho...mere logic mein galti batao...

the mistake in ur logic is that anion on B is not stabalised ..whereas the anion on A and C is stabalised....and in A we have both inductive and resonance effect but in C we have only inductive...and i quoted that values just to show that Hydrogen Bonding doesnt make a huge difference in the case of NO₂

eureka we discussed this. a) is the most acidic due to ortho effect. Same reason in Q2 :)

In Q3 we shall not decide acidic order by resonance stabilisation. Meta position is not affected by resonance. Now both methoxy and chlorine groups have -I effects. But chlorine being a halogen has the strongest -I here, so the second compound is most acidic.

ya..so 2 is more acdic naa for Q3 ??
i ahd dbt becoz ans given was 1

Yes it should be 2. I'm positive about that.

thx.thread closed

tables dont decide acidity in exam hall [1]

i feel convinced by the discussions done

mere bolne ki kya jaroorat thi?? I had uploaded my table naa?? [3]

btw ans is correct

pKa table