isomeric alcohols

How many isomeric alcohols are possible with the formula C3H5OH?

16 Answers

1
Yogesh Singh ·

2
propan-1-ol
propan-2-ol

1
Kumar Saurabh ·

prop-1-en-1-ol
prop-1-en-2-ol

1
Akshat Mishra ·

kumar has given the two isomers
but there are others also like
prop-2-en-1-ol
cyclopropanol

1
abhishek kumar ·

I think kumar and akshat have given the right answer.
So 4 isomeric alcohols are possible for C3H5OH

prop-1-en-1-ol
prop-1-en-2-ol
prop-2-en-1-ol
cyclopropanol

1
Aneesh Gupta ·

What about the geometrical isomer of the compound?
I think there exist 1

1
Wasim ·

There exists geometrical isomer of prop-1-en-1-ol

1
voldy ·

there are 2 isomers possible.
prop-2-en-1-ol
and cyclopropanol
think and assure yourself . Else I'll give the answer on the day after.

1
abhishek kumar ·

I had already given these two isomers.
I want to know if more exist

1
voldy ·

I'm sorry . I should've said there are ONLY TWO ISOMERS (STABLE) POSSIBLE .Others are hypothetical and don't exist. the ones gien byme exist . Try to find out why the others don't exist , It's part of basic Organic chem . I'll give the answer later.

33
Abhishek Priyam ·

Hey lord, although prop-1-en-1-ol
prop-1-en-2-ol exist mainly in in keto form, U can't call them non existant. In isomers of alcohols u have 2 name them..

62
Lokesh Verma ·

yup.. in exams it will be a big mistake in such problems not to name all isomers... regardless of whether they may or may not exist!

1
voldy ·

Thanks Nishant and Abhishek . I never knew that.

1
~AjInKyA~ ·

HEYYYYYYYYYYY
U MISED1
PROP 1 EN 3 OL
ALON
prop-1-en-1-ol
prop-1-en-2-ol
prop-2-en-1-ol
cyclopropanol

SO NOW 5 ISOMERZZZZZZ
>>>>>>>>>>>>>>

1357
Manish Shankar ·

Ajinkya you have made a mistake

there is no compound as such PROP-1-EN-3-OL
it is named as PROP-2-EN-1-OL (as alcohol should be low numbered)

1
~AjInKyA~ ·

ooooooooo
tanx manish
in hurry i i bcam sillly
nextime i wont b
>>>>

1357
Manish Shankar ·

yeah
take care of these small things otherwise you will lose marks on the easiest problem

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