Organic.....Straight from arihant....

7.C
30.A
will try rest tomorrow![1]

14)c

Boiling point of a compound decreases with increase in branching as the surface area decreases...So the I should have highest b.p

Its reverse for M.P..Melting point increases with branching.

22)b?

30 the ans given is b

for 14) But here why is KMno₄ not oxidising the alkane to acid....is it due to the fact that it is 3 degree??

also for that 22....

CETANE NUMBER

1-methyl napthalene...cetane no..==0

octane number

heptane ...octane number ==0

Arihant Organic chem..pg 230

so shud'nt it be a??

7) Will go with A.

14) C (Can't oxidise to acid, methyl groups aren't gud leavers, so it can fight with only the Hydrogen... also, KMnO₄ inserts Oxygens wherever it can find the place..!!)

30) B (Secondary "H" wud be replaced...making the carbon have 4 diff. groups- H, Cl, Me, Et)

yup i also give it : 7 : A)

because in 2 and 3 the S.A of the molecule being decresed the Vander Waal's forces are reduced .....so the M.P and B.P will be less for 2 and 3.

so ans : A

from which chapter are these questions taken ????

Sandipan Please inform me .

And who will be reponsible fr the Elimination....?
None, not KMnO₄, not unless we introduce a dehydrating agent.

& moreso, can't/don't we get tert-Hydroxides as products in reactions...?
Its just the KmnO₄ action we need to look upon, rather than foreseeing the future fr future reactions.

Since when did KMnO₄ start reacting with tertiary stuff anyway..

Oh!....but it does here :D

Kyunki only a tiny tert-Hydrogen is at stake, not a difficult-to-chase-out functional group. :P

Phir toh OH hi ban sakta hai...nothing else it can do!