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7 Answers

3
msp ·

1
°ღ•๓яυΠ·

carbocationwill b formed teriary n cn- will go thr n br on d othr side

wild guess

1
°ღ•๓яυΠ·

i guess ulta sankarna
cn will go on d upper carbon n br on d lower

3
msp ·

cn molecule larger than br molecule .if cn will be at the upper carbon then it will steric hinderance which is more unstable

1
°ღ•๓яυΠ·

tertairy carbocation will b forrmd coz tahts more stable

ps: sorry if ma thinkin is wrng mah org sucks

1
voldy ·

nice integrations is right .

sankara's product is right if he replaces Br by CN and Cn by Br.

here the reactant can be split as BrCN i.e Br+ CN-

hope it's clear

24
eureka123 ·

show the stereochemistry too.........thats the prob here.......[2]

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