3oye grandmaster..wats the answer ????
I feel its D...bcoz negative charge on C is least stable among all....
which will be most basic in aqueous med.
a)CH3-C=O-NH2 (-NH2 IS LINKED WITH AND NOT O
B)CH3-C=S-NH2
C)CH3-C=NH-NH2
D)CH3-C=CH2-NH2
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21Oh so u mean 2 say, leser the e-negativity of the C attachd to N more da basicity huh!
lagta hai sahi kyunki thn only will it want to accept H+
1yup... hydrogen bonding should affect ...
and also water will donate protons to reqd places.....
1yup,yup,yup...sky approach was quite right....to cater for h-bonding but the ans is C.
I don't believe it. actually the point is stabilisation of -NH2+ in each case and if u see here resonance destabilises the carbocation in each case...
so my ans is d) where delocalisation is min. (as = [double bond] electron is less mobile than lone pair ) so there is min resonance and min destabilisation.
Plz comment
3hey sky...whn v consider aq medium, v mostly take in2 account H bonding and solvation of NH2+ ion...in each ot these cases, the type of substituent attached to NH2 mainly affects bcoz of the steric structure....
no in this case, i think all v got to do is evaluate electron density on N of NH2, as all are almost same whn it comes to steric effects....