sn1

but wat will be the relation between the first and the third

seems to b a gud enough reason i guess

diphenyl>t-butyl>phenyl
sory abhi din saw ur ans but i can giv the reason
1. double resonance is ofcoarse is the strongest
2. for t-butyl & phenyl t-butyl is ahead as
a) 9 hyperconjugetion for t-butyl
b) some amount of -I effect goes against phenyl

ya abishek you are right, can you tell the reason

on waht basis?

:(

I thought diphenyl>t-butyl>phenyl

t-butyl > diphenyl > phenyl.

but my teacher told that first one is more stable , it is experimentaly found...............

between the first n the third also i think it will be third one.. (resonance..)

the second compound will be more reactive towards Sn1 as the carbocation will be resonance stabilised over two rings
whereas in the first case there will be no resonance

the answer for Sn1
(CH3)3C-I & (Ph)2-CHBr
is (Ph)2-CHBr>(CH3)CI.

hmmmmmmm .....
aapk sahi ho .....i thought sumthing else

jaha tak mujhe yaad hai (:P) ... sn1 has stability of carbocation concept...
toh yaha pe nucleophile kaha se aya?

next thing,,,, wen thr will be a positive charge on C in case of 2nd ocmpound, there are TWO benzene groups to stabilize that positive charge... so my ans is 2nd one...

ii guess (ph)ch2br
cozx here nucleophile will attck so positive charge shud b more thus ........wen 2 ph groups r ther positive chrage decreses due to -! effct thus
i guess that's d asnwer ie phch2br ........

I THINK (Ph)2-CHBr... coz two benzene groups attached... so more e-density than in case of the third one...
(can be wrong)

and what will be the answer if
(CH3)3C-I , (Ph)2-CHBr & (Ph)-CH₂Br