What is "charge separation" in case of resonance and acidity of organic compounds?

JEE Main Sample Questions › Organic Chemistry questions › What is "charge separation" in case of resonance and acidity of organic compounds?

This question relates to dissociation of Methanoic Acid (HCOOH) to Methanoate ion (HCOO^-) in H₂O Solvent.

HCOOH + H₂O -> HCOO^- + H₃O⁺

A book says there is delocalisation in both methanoic acid and methanoate ion but it will be ineffective for the acid, as resonance in methanoic acid involves "separation of charge" , so it will discourage the recombination of proton with the anion formed and equilibrium is shifted to the right side.

How charge separation resists recombination of proton ??

this is related to resonance affecting acidity of methanoic acid.

#Chemistry #Organic Chemistry

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Basic Integral Calculus Operators Symbols Matrix Cases

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° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

What is "charge separation" in case of resonance and acidity of organic compounds?

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