Why diff products r formed....in this case.....??

2- Bromo-2-methyl-propane gives two different products with

1. CH3CH2ONa in presence of CH3CH2OH

and

2. CH3CH2OH alone.

WHAT R THESE PRODUCTS AND WHY ARE THEY DIFFERENT WHEN THEY BOTH PRODUCE SAME ANION i.e. CH3CH2O- ?

4 Answers

23
qwerty ·

CH3CH2OH is a weak acid.

CH3CH2OH → CH3CH2O-+H+

dis equilibrium is more towards left. hence conc of CH3CH2OH >>CH3CH2O-

hence in ethanol , ethanol will react

1
venkateshan ·

in the first case the product will be alkene i.e., 2-methyl prop - 2 - ene and in the second case... it will be ether.. i.e., 2 Ethoxy 2 methyl propane....

1
venkateshan ·

i am sry... it will be 2 mythyl propene.. in the 1st case...

1
euracle ·

Pls give reason..........

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