2 easy qsns....

1)The nodal plane in the Î bond of ethene is located in :-
i) Molecular plane
ii)Plane parallel to molecular plane
iii) plane parallel to molecular plane and bisecting C-C sigma bond at rt. angles
iv)Plane perpendicular to molecular plane containing C-C sigma bonds.

2) Molecule possesing both sp3 and sp3d2 hybridisation is :-
i) Solid PCl5
ii) Gaseous PCl5
iii) PCl3
iv) None of the above.

16 Answers

19
Debotosh.. ·

answer to second one is (i)solid PCl5....it exists as [PCl4+ ][PCl6-]

11
Gone.. ·

Ans to second one is (i)

Solid PCl5 exists as [PCl6-] and [PCl4+]
[PCl6-] is sp3d2
[PCl4+] is sp3

You want me to draw their structures ??

19
Debotosh.. ·

yes...edited !

11
Gone.. ·

@ organic :
i think you got confused with PBr5 which in solid state exists as PBr4+ and Br-

1
aieeee ·

the two p-orbitals that overlap to form the pi bond must be parallel to each other for maximum overlap to occur.this forces the transition state formed by one carbon and two hydrogens must lie in the same plane as the transition state formed by other one carbon and two hydrogens .this means all six atoms lie in the same plane and electrons in p-orbital occupy a volume of space above and below this plane.

The nodal plane in the Î bond of ethene is located in Plane parallel to molecular plane.ans is b.

1
kartick sharma ·

ans of 1) is d so that overlaping will be better

1
Unicorn--- Extinct!! ·

i think ronald is right..the answer has to be i).

11
Devil ·

Thanx all of u for the participation.....now 1 elementary qsn, what is the hybridisation of Carbon in graphite......U'll be shocked to know the ans given at the end of the book.

19
Debotosh.. ·

sp2.....this was very simple !

19
Debotosh.. ·

The geometry of the hybridized orbital is trigonal planar. This is the reason why each carbon atom within graphite has three nearest neighbors within the graphite sheets. One of the p-orbitals is left unaffected. This last p-orbital overlap with those from neighboring carbon atoms, in a sideways manner, to form the distributed pi-bonds that reside above and below each graphite sheet.

11
Devil ·

And now the ans at the end of the book for the hybridisation of C in graphite :-
sp2+Î 3

1
Unicorn--- Extinct!! ·

sp2+Ï€3 !!!!!!!!
Which book?

11
Devil ·

Our gr8 "Fiitjee"...

1
Unicorn--- Extinct!! ·

[9]

19
Debotosh.. ·

what i can say over here is that there must have been some other question given along with this one,whose answer turns out to be (∩/3)!!!

11
Devil ·

Why don't u check for urself to clear this confusion.....
Quiz "Chemical Bonding"
17th qsn!

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