how did u get that formula???????
Ionic product of D2O is 1.33*10-15.For what value of pD will the solution be acidic?
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3 Answers
Kumar Saurabh
·2008-11-01 05:47:55
for acidic
pD should be less than -(1/2)(log1.33*10-15
pD<7.438 for acidic solution
Kumar Saurabh
·2008-11-01 12:37:42
D2O [eq] D+ + OD-
[D+][OD-]=Kw and [D+]=[OD-]
[D+]=3.647*10-8
pD=7.438 for neutral solution
pD<7.438 for acidic solution