Atomic Structure

The first ionization energy of H is 21.79x10-19J.Calculate the second ionization energy of He atom.
(According to me,
2nd I.E of He=E2-E∞
=(21.79x10-19)x2222-0 (E=21.79x10-19xz2n2)
=21.79x10-19J given correct answer is 87.16x10-19J...!!!! )

2 Answers

111
Rajiv Agarwal ·

You have made a fundamental mistake here. Can you figure out your mistake?

158
Anik Chatterjee ·

ya...i think i should have found out the energy required to remove the 2nd electron in He+ in the first shell itself....isn't it?

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