Basic doubts in chemical kinetics

please explain the concept clearly
Q3.for a reaction ,rate expressions is given as----- RX+OH-=ROH +X- rate=4.7*10-5[RX][OH]+0.24*10-5[RX] wHAT PERCENT OF RX REACT BY SN2 ?WHEN [OH]=0.001M.

6 Answers

1
Avinav Prakash ·

2.> exothermic reaction occurs>>increasing temp favours backward reaction...(b)

3.>SN2 means the rate follows bimolecular path ie.both halide as well as OH- will depend..now u can calc to get the answer

for q1..im not sure is the ans:10 seconds

1
ajoy abcd ·

the ans are 1.(c),2(b) 3.-----5

3
rocky ·

for question 3--

for SN2 rekn.

for first case % of this reaction takes place by the SN2 mechanism =

4.7*10-5[RX][OH]4.7*10-5[RX][OH]+0.24*10-5[RX]

now put the value of [OH]=0.001M. and cancel [RX] and get the answer

1
ajoy abcd ·

please try the first one...

62
Lokesh Verma ·

1 requires solving the differential equations

dA/dt=-k1A

dB/dt = k1A-k2B

dC/dt = k2B

if B is max then dB/dt =0

A=A0e-k1t

Now solve...

1
ajoy abcd ·

Oh yes....lovely technique....
thank you sir..

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