chck ma answer

for rxtion PCl5 --- > <---- PCl3 +Cl2

in agesous phase Kc=4
in 2liter flask thr r 2.5 moles iniially of each PCl3 n Cl2
equilibrim conc of PCl5 is

m gettin it as .8 check wher thats rite

11 Answers

1
°ღ•๓яυΠ·

arey ni i did that also
teko jo answer mila woh options mein ni hai

optionz r

.25
.125
.75.............. (mera iske karib hai)
1

11
Mani Pal Singh ·

SORRY MADE A BLUNDER EARLIER

VOLUME KO 4 LE LIYA THE

I AM GETTING 0.25

106
Asish Mahapatra ·

PCl5 = PCl3 + Cl2
0 2.5 2.5
a 2.5-a 2.5-a at equilibrium

So, 4 = [(2.5-a)/2]2/(a/2)
==> 8a = 25/4 + a2 - 5a
==> a2 - 13a + 25/4 = 0
==> 4a2 - 52a + 25 = 0
==> a = (52±48)/8 and + sign can be ignored bcz .. a<2.5
==> a = 4/8 = 0.5 ??

so equilibrium conc of PCl5 at equilibrium = a/2 = 0.5/2 = 0.25

1
°ღ•๓яυΠ·

aapne ulta kara hai ji

dekh liyooo

nt in options

106
Asish Mahapatra ·

@mani maine volume ko divide kiya hai

11
Mani Pal Singh ·

MRUNAL ANSWER KYA HAI???

1
°ღ•๓яυΠ·

haan ji thanks answer ni pata bansal notes se hai
answer key ni hai

1
Anuj ·

@mrunal, v can do it by the reverse process too.......

1
°ღ•๓яυΠ·

haan ji i noe dat i did dat

neways thanks :P
btw aap akun ho ?

1
Anuj ·

i m scientist...[3]

@nishu bhaiya, pink milega??????[7][4][3]

1357
Manish Shankar ·

@ scientist.

you have made a small but huge mistake

At equilibrium
As coefficient of all the terms are 1

if 'a' mole of PCl3 is gone then only 'a' mole of PCl5 is formed

How 2a is formed in your case

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