Chemical Equlibrium_1

When heated, NH₄COONH₂ decomposes as below:

NH₄COONH₂(g)â†’2NH₃ + CO₂

At a certain temperature the equilibrium pressure of the system is 0.318 atm.Find the K_p for the reaction..

2 Answers

106

Asish Mahapatra ·2009-10-28 00:31:27

NH4COONH2 = 2NH3 + CO2
t=0 1 0 0
t=teq 1-a 2a a So P=1+2a=0.318(givn)

p(NH4COONH2)=(1-a)/(1+2a)
p(NH3) = 2a/(1+2a)
p(CO2)= a/(1+2a)

Kp = [CO2][NH3]²/[CH3COONH2]

which can be calculated

[] means partial pressure

thanks dude..

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