DOUBT-CONFIRM

ques- PF3 CAN ACT AS A DONOR MOLEULE WHEREAS NF3 SHOWS LITTLE TENDENCY TO DONATE.ACCOUNT FOR THIS FACT.

ITHINK THAT IN PF3 ELECTRON PAIR IS EASILY DONATED AS PHOSPHORUS IS LARGER IN SIZE THAN NITROGEN.IS THIS EXPLANATION CORRECT.IF YES PLEASE CONFIRM.

9 Answers

1
Akand ·

donate wat??????
pair of electrons?????
NH3 shows little tendency??????
then wat about NH3 donating to BF3???????
thts a usual one naa????

1
JOHNCENA IS BACK ·

see do u think i don't know that

this is a conceptual question of top selling iit book.

but the answer is not given.so i sent my answer.
i just want if the ans. is coreect or not.if not,then you use ur brain and send me correct answer

1
greatvishal swami ·

akand NH3 amd NF3 r diff

1
spiderman ·

i dont know whether m corect or not vishal is chem expert so pls just check my answer
NF3 has lone pair but three fluorine atoms are also present so they cause a reluctance to share and since nitrogen is small it has a small though concentrated cloud which is pulled by 3 fluorine ... in PF3 can act as donor as diffused cloud and fluorine makes bond with d orbital not present in nitrogen diffused cloud causes less tendency to share but more than NF3
nishant sir please check .. [2]

1
JOHNCENA IS BACK ·

need a confident reply.

1
spiderman ·

at least check whether m correct if not tell my flaw

1
JOHNCENA IS BACK ·

spiderman,
it is worthless to say that wat u wrote in ur reply the same reason i also gave in my first reply itself and i want nishant sir to check it.

1
spiderman ·

phosphorus is larger so wat ? does that mean it will denote less? u need to tell na that why still it will denote more electron density than NF3 .... yaa let nishant sir check ....

1
JOHNCENA IS BACK ·

i don't say u r wrong.i just started thred to confirm if i guessed correct.now there is no point in u arguing with me u are guessing as well.i meant in my previous reply that wat i wrote in my first reply is same as ur reply and i didn't write the reason i thought which u wrote.

so please don't argue.

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