13wat should be the ans??
bhaiya plz.....
Al2O3 is reduced by electrolysis at low potentials and high currents.If 4*104A current is passed through molten Al2O3 for 6 hours,mass of aluminium produced....
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22 Answers
13thanx Manish bhaiya....i became confused...tx riddle...[1]
13bhaiya... they asked for mass of Al produced.... not Al2O3 consumed
3 electrons give 1 atom or molecule of Al...is n't it?[7]
62coulomb
6 x 3600 x 4 x 10000/ {6 x 6.023 x 1023 x 1.6 x 10-19 }x102
13bhaiya...i m finding nothing wrong in RIDDLE's solution in post #4
me too getting that...but how 1.3 x 104???
13bhaiya...plz post the method
i left it in today's AIPMT paper..:(
13options given were in grams
2.4*105
1.3*104
9.0*103
8.1*104
13wat ans did u get...mani n Nishant bhaiya???
This Q is actually from today's AIPMT paper....
11yaar abhi bahi uske electrolysis ki conditions batai hain
ab iss mein kya question ???
and reply to #5
13bhaiya...din understand ....2.3 x 1023??
wat is the mass??
13why is it mentioned that
at low potentials and high currents...
62Al3+-> Al
so for one mole of Al2O3, 6 moles of electrons are passed
= 6 x 6.023 x 1023 x 1.6 x 10-19 coulomb
total charge passed in 6 hours = 6 x 3600 x 4 x 10000 coulumb
now divide and you will get the answer :)
this will give the no of moles..
11bhai iss mein EQ WEIGHT M/6 leenge
have u tried like this [7][7]
1Al +3 each mole requires 3 electrons ...
so wt. = 27/3 * 6*60*60 *4*104 / 96500 =