electrochemistry 1

JEE Main 2015 Preparation › Physical Chemistry questions › electrochemistry 1

A lead sorage cell is discharged which causes the H2SO4 to change from a concentration of 34.5% [density=1.26 g/ml] to one of 27 weight%.The original volume of electrolyte is 1 L.How many faraday`s have been left at the anode?
The overall reaction during the discharge is

Pb(s)+PbO₂(s)+2H₂SO₄â†’2PbSO₄(s)+2H₂O(l)

#Chemistry #Physical Chemistry

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2 Answers

1

skygirl ·2009-01-01 19:33:23

this is similar to your other question..

i solved that one.. check it...

if u have ne prob there .. post agn :)

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skygirl ·2009-01-02 19:36:14

did u get it??

no response?? [7]

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Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

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+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω