1plz n e 1 help
An element 'A' forms 2 oxides , the weight ratio composition in them, A:O =[ x : y ]in the first oxide and... [ y : x ] in the second oxide. If the equivalent weight of 'A' in the first oxide is 10.33 , calculate the equivalent weight of A in the second oxide.
-
UP 0 DOWN 0 0 5
5 Answers
21let the first oxide be A(2)O(p)-----valency of A is p, let the atomic wt of A be m, so m/p= 10.33
so, 2m/16p = x/y
let the second oxide be A(2)O (q)-------valency of A is q in that compound
again,2m/16q=y/x
solving above 3 equations u will get m/q=64/10.33 which is nothing but the equivalent of A in 2nd compound..