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Q.1
Find the % of H⁺ from water at 25⁰C in 0.1 M CH₃COOH take Ka of acid as 10^-4 Kw=10^-14 and volume = 1L.
(Give complete solⁿ.)

4 Answers

[H+] = âˆš( K_a . c) = âˆš(10^-4 ( 0.1) = 3.16 x 10^-3

Thus , [OH-] = 10^-14 / (3.16x10^-3) = 3.16x10^-12.

This is due to water , which is equal to the [H+] contribution by water.

so , % contribution by water is 10^-7 .

i too got 10^-7 % contribution frm water but i did in a diff method ..... took common ion into consideration...
i didn get srinath's method :(

1357

Manish Shankar ·2008-10-25 02:30:35

srinath had neglected the [H⁺] from water initially and you have neglected it in equations.
that's the only difference

so sky didi is correct????isnt it???

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