The rate of diffusion of a sample of ozonised oxygen is 0.98 times more than that of pure O_{2}. Find the percentage (by volume) of ozone in the ozonized sample. also tell percentage by weight.

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1 Answers
Manish Shankar
·20120812 04:14:52
let the mole fraction of ozone be x and oxygen will be 1x
Molecular weight of mixture=x*48+32(1x)
so we have
(16x+32)/32=1/(0.98)^2 WHY ?
x/2+1=1.04
x=.08=8%