An open vessel at 27°C is heated until the 3/5 of the moles of the air in it has been expelled. Assuming that the volume of the vessel remains constant, what is temperature to which the vessel has been heated.
a) 27°C
b) 300°C
c) 477°C
d) 110°C
Answer: (c)
Please explain the method to solve this one?
71After 3/5 moles has escaped, what has remianed is 2/5 moles. Now Initially the same volume was occupied by 1 mole of gas at 300 K is occupied now by 2/5 moles of air at T.
So, Initially, 1 . V = 300 .R .1
Finally, 1 . V = T . R . 2/5
Solving T = 750 K = 477 ° C
1omg.... i was applying all rate of effusion formulae....
Anyways thanks :)