i 4gt hw 2 do this

solution containin 3.24g of non volatile solute non eltorlyte and 200g water boils at 100.130 at 1atm wats d molclr mass of solute

we dnt hav Kb na

hw 2 do then i 4gt :'(

19 Answers

1
°ღ•๓яυΠ·

na

1
°ღ•๓яυΠ·

wah..............baccha.............itna mat padh

24
eureka123 ·

ohho.....i completely misinterpreted Kb....i thought u r talking about dissocation constant of weak base..[3][3]

silly me....[9][9]

1
°ღ•๓яυΠ·

k just calld ma miss....she said yaad rakhne hai values :(

1
°ღ•๓яυΠ·

na ........

1
sriraghav ·

wats....
Did u compare any two quantities (lyk dividin) so that kb gets cancelled out .....i doono

1
°ღ•๓яυΠ·

arey i mean thses type of q's ...bt here i m wonderin ova Kb................ :'(

1
°ღ•๓яυΠ·

ya bt u need latent heat 4 dat na

1
sriraghav ·

ya.... usin latent heat(i think u hav to remember this)

Kb= (0.02 * T2)/ l2

where T is normal boilin point of pure solvent(here it is water)
and l is latent heat of vapourisation in cal/g

1
°ღ•๓яυΠ·

nthng gven

24
eureka123 ·

we need Kb???

11
Anirudh Narayanan ·

are u not getting the answer by putting Kb = 1.86??

1
°ღ•๓яυΠ·

r u sure

thrs sum method wer u dnt need kb
i mean kuch hoga na .q cnt b so wrng .n hw can they assume that we rembr

11
Anirudh Narayanan ·

we must remember that Kb of water = 1.86 as mani said

1
°ღ•๓яυΠ·

eureka post d solution

1
°ღ•๓яυΠ·

ya ..we dnt ....post ur method

delTb=mKb
??

24
eureka123 ·

i was asking why we need Kb???

11
Mani Pal Singh ·

Kb ko 1.86 le ke check kariyo

1
°ღ•๓яυΠ·

ya bt nt given

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