The ionization constant of NH4+ in water is 5.6 x 10-19at 25 C.The rate of constant of the reaction of NH4+ and OH- to form NH3 and H2O is 3 x 1010 L/mol s.Calculate the rate constant for proton transfer from water to NH3.
1357NH4++OH-=NH3+H2O
K=Kf/Kb=[NH3][NH4+][OH-]=Ki/Kw
Kf, Ki and Kw are known, so you can find Kb
I think this will do
is the answer not matching???
1K=[nh3][h2o]/[nh4+][oh-]=kf/kb; kf=forward reaction and kb=backward reaction
Ki=[ nh3][h+]/[h2o][nh4+]; ki=ionization const.
K/ki=[h2o]^2/kw; kw=ionic product of water and [h2o]^2 is a constant
Therefore, k/ki=1/kw
Therefore we substitute k=kf/kb
We get-kf/kb=ki/kw
Kb=kf×kw/ki
