Ionic Equillibrium

Ques.)

2 moles of PCl5 are taken in a closed vessel. At equilibrium the vessel contains 2.5 moles. The degree of dissociation of PCl5 is

1. 0.25

2. 0.5

3. 0.4

4. 0.2

9 Answers

1
Akshay Pamnani ·

1.0.25

13
Avik ·

I think he's talking about Total moles.

Then, Akshay bhai is rite.

29
govind ·

@ E= mc2
This question is from chemical equilibrium and not ionic..

@manmay
2.5 moles of the mixture of gases including PCl5 , PCl3 , Cl2

and Ans is 1

49
Subhomoy Bakshi ·

PCl5 -----> PCl3+ Cl2
2 moles
2-a a a

no of moles= 2+a

2+a=2.5

a=.5

degree of dissociation=0.5/2=0.25

1
E=MC^2 ·

@Subhomoy~ : " " degree of dissociation=0.5/2=0.25 " "

This was my dbt ??

Y to half it ??

Isnt a deg of dissoscn

29
govind ·

Well the way subho did it may create some confusion so lemme do it in the actual way..

PCl5 ≡ PCl3 + Cl2
at t=0 C 0 0

at equilibrium C(1-α) Cα Cα

where C is the intial concentration and α is the degree of dissociation

so according to the question C=2 and finally we have 2.5 moles

C - Cα +Cα + Cα = 2.5
2+ 2α = 2.5
2α = 0.5
α = 0.25
i hope the confusion is cleared now

1
E=MC^2 ·

Ya Govind Thanks a lot

& btw the title was a mistake (In a hurry I was solving miscellaaneous probs so i posted wrong heading )

29
govind ·

Wen did I say that subho did it wrong?

I just told my method to make things clear for E = MC^2 ..since subho was offline by then

and that regarding that concentration and moles thing....take the volume of the container as 1 lt

1
Bicchuram Aveek ·

yup...missed that bit !!! sorry dude :-)

Your Answer

Close [X]