Among KO2, AlO2-, BaO2 and NO2+, unpaired electron is present in
a) NO2+ and BaO2
b) KO2 and AlO2-
c) KO2 only
d) BaO2 only
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1 Answers
garima kalakoti
·2017-03-31 06:25:28
Electrons present
NO2+= 7+16-1=22
BaO2=56+16=72
AlO2-=13+16+1=30
KO2 = 19+16=35