1[H30+] = 10-10+10-4
2
= 5.000005*10-5
now take log and solve.
is the ans around 4.3
please correct if wrong.
Two solutions of equal volume, but one having pH 4 and other having pH 10, are mixed. What is the pH of the resulting solution?
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9 Answers
1
1ya, even i did the same...but ans given is 7 (kya pata book waalon ne average le liya ho galti se!!! :D)
11The Ques is same as
Calculate the pH of the solution obtained by mixing equal volumes of 0.0001 M HCl & 0.0001 M NaOH.
eq. of HCl = eq. of NaOH
So,resultant soln. is neutral. ∴ pH=7
Calculation of pH of a mixture by the method given by ankit,can be used only for 2 acidic solns. or 2 basic solns.
1the book seems to right
2nd one is basic dat means there must 10 to power -4 oh- ions and it will neutralise the first one and thus neutral......i.e ph is 7 .......!
62my wrong..
manish just pointed this out to me...
[H30+] = (10-10+10-4)/2
[OH-] = (10-10+10-4)/2
Now both can react back to form H2O
so the concentration will fall back to value of such that pH=10-14
So [H+]=10-7
1yup......................
4 5 6 7 8 9 10................4 is equally far from 7 as 10 is ............ie both are either 3 more or 3 less...........................so the pH becomes 7............(neutral)