shortcut

is there any shortcut to determine whether a species is paramagnetic or dimagnetic without actually writing the electronic configuration?

6 Answers

39
Pritish Chakraborty ·

Well for our syllabus, apart from NO- and O2, all molecules with integral bond orders are diamagnetic (the exceptions I mentioned are paramagnetic due to Hund's rule which causes singlet occupation in 2p orbitals). The ones having fractional bond order are paramagnetic. This is a rough rule which works within the scope of our syllabus.

To find bond order, there is a nice quickie method my friend told me. Msg me in my chatbox and I'll tell you.

29
govind ·

Well as far as i know the shortcut comes from practice

@Pritish
Share ur knowledge here in the thread that will be better..

21
amit sahoo ·

i found out this on one of the discussions here on tiit.

21
amit sahoo ·

pritish is this the shortcut you were talking abt or something else?

39
Pritish Chakraborty ·

Well since it's being demanded so much....here it is. It requires a little knowledge of the periodic table.

Steps to find the bond order -:
1. If the element is in a group number less than 8, then subtract 8 from its group number. For eg, nitrogen = 7, oxygen = 8, fluorine = 9, etc.

2. Add up such numbers from each of the constituent atoms. For eg, for N2, 7 + 7 = 14.

3. Subtract 8 again.

4. After this subtraction, with the number you have left, you put 6(REQUIRED at all costs...if you have a number smaller than 6 after subtraction, put all you have) into the bonding orbital. After putting minimum 6 into bonding orbital, put the rest into antibonding orbital.

5. Now you can easily find bond order.

Let's do this by example. How about N2?
1. 15 - 8 = 7.

2. For two N atoms, 7 + 7 = 14.

3. 14 - 8 = 6.

4. NB = 6, NA = 0 [These are not the actual figures of electrons in those orbitals. Just for the formula]

5. BO = 1/2(6 - 0) = 3 which is indeed so! N2's triple bond shows here.

1
rickde ·

gud one..u can use this also......

count the number electron in outermost orbit in the atoms...
add em up

let it be n

if n=10 ....BO=3
n=11... BO=2.5

and the BO decreases by 0.5 for each successive electron added

similarly for backwards...
n=9....BO=2.5
n=8....BO=2......n so on

Eg....

for oxygen...6 electron in outermost
so n=12....BO =2

for NO....outermost electrons...n=5+6=11
so bond order 2.5

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