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In mineral A₂B, atoms B form CCP structure while A atoms occupy the voids within this structure. What are the coordination numbers of atoms A and B ? Name the voids in which atoms A are present and what fraction of these voids they occupy?

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aieeee ·2009-12-13 21:42:34

I guess this represents an anti-flourite structure.

coordination numbers of A and B are 4 and 8 respectively.

A occupies all the tetahedral voids .

now, if around B , 8 tetrahedral voids are filled by A, then der would be four octahedral voids.
thus, the fraction of voids occupied = 8/12 = 2/3

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mentor_Layak Singh ·2009-12-13 23:38:37

B atoms form CCP structure
Number of octahedral voids = Number of B atoms
Number of tetrahedral voids = 2 x Number of B atoms.
Since the number of A atoms = 2 x Number of B atoms therefore they occupy all of tetrahedral voids.
Coordination number of A atoms = Four as they occupy tetrahedral voids
Coordination number of B atoms = Twice the coordination number of A
Since B atoms are half of A atoms therefore their coordination number is twice the coordination number of A.Coordination number of B = 8.

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