# States of matter

A closed vertical cylinder is divided into two parts by a frictionless piston, each part contains one mole of air. At 27Â°C, the volume of the upper part is 4 times the volume of the lower part. Calculate the temperature at which the volume of the upper part is 3 times the volume of the lower part..

PLS GIVE COMPLETE SOLUTION AND BEAR WITH MY STUPID DOUBTS

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JOHNCENA IS BACK ·

IF U UNDERSTOOD UR MISTAKE THEN PLEASE REPLY SO THAT I CAN LEAVE THE FORUM.

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JOHNCENA IS BACK ·

it will be far better for me to save time coming to forum and spending hours to check if one has solved them or not.i would better leave the forum and study myself as i used to do earlier.someone told me on goiit that it is good forum where u surely get a nice reply to solve ur queries.......may be i got rong info......i will see if that is so today at 8.

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JOHNCENA IS BACK ·

see i was forced to think like that,i try to help others as i can,so,i also deserve my queries be solved by nishant sir.........don't i.

then i don't think if it is harsh.i will again peep into forum at today 8 pm to check if my queries have been solved,if not,then bye.........

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JOHNCENA IS BACK ·

let me see if i find that behaviour of nishant sir changes(he starts replying to my queries) then i may change my decision.

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Anirudh Narayanan ·

don't u think that's too harsh ??

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JOHNCENA IS BACK ·

strider,

i don't want to hurt u by not replying to ur friendship offer.

but i thing i am being neglected by nishant sir and this forum(few people on forum of course not u) don't need me on the forum.so i think i should leave the forum for ever.ya...but if i chose to remain i will surely love to have a friend like u.

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JOHNCENA IS BACK ·

oh ur reply came while i was typing.

btw...i got it right by using the best god gift-brain.

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JOHNCENA IS BACK ·

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Anirudh Narayanan ·

I KNOW WHERE I WENT WRONG

BUT I DUNNO HOW U GOT IT RIGHT...

1
JOHNCENA IS BACK ·

PLZ REPLY SO I CAN LEAVE.

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JOHNCENA IS BACK ·

ARE YAAR LAGTA HAI KAL JAISIE AKSHAY KE KARAN SHAAM GAYI VAISE HI AAJ BHI JAYEGI..

OK...LEAVE IT.

NOW
U WILL GET FINAL ANS. WHEN U PUT C AND Cf VALUES IN IT.

I SAY C AND Cf ARE DIFF.......UNDERSTOOD.(DIFF. TEMP)

U DON'T KNOW C ,U DON'T KNOW Cf
SO IN YOUR FINAL EQUATION U CAN'T PUT THEIR VALUES.

SO U CAN'T GET THE ANSWER.U DID NOT CONSIDER THESE CONSTANT AND SO GOT THE ANSWER(WRONG) BY WRONG METHOD.........I THINK NOW U UNDERSTOOD HOW I ACCOUNT FOR THIS.

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Anirudh Narayanan ·

so how will u account for the different constants??

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JOHNCENA IS BACK ·

at 148.875 degree celcius

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JOHNCENA IS BACK ·

OK

SEE IN UR SOLU. U URSELF SAID THAT
P IS INV. PROP. TO V...RIGHT

SO,NOW THERE IS A CONSTANT C ALSO INVOLVED IN P VALUE....OK.

IN LATER CASE (UPPER VOL. 3TIMES CASE) THERE ALSO A CONSTANT Cf INVOLVED. Cf IS DIFF. FROM C AS IN TWO CASE TEMP. IS DIFFFERENT.

YOU DID NOT CONSIDER THIS IN UR SOLU. THAT'S WHY WRONG ANS.

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Anirudh Narayanan ·

pls find the mistake in my solution b4 u go

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JOHNCENA IS BACK ·

friend maybe u got pink as it was in ur luck.oh anyways it doesn't make any difference to me. cheers!!!!!!!!!!!!!!!

BEST OF LUCK

FOR UR PREPARATION.

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Anirudh Narayanan ·

dg, find the mistake in my solution da

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JOHNCENA IS BACK ·

of course,at first i did not post the solution as there wud hav been no point in posting wrong solution if my ans. was wrong.

method-

first calculate initial pressure of upper and lower parts.A be area of cross section of piston.

then,we have
P(low)A=P(up)A+mg

calculate mg.

then calculate final pressure of upper and lower parts.

then,
Pf(low)A=Pf(up)A+mg

all variables except temp. will get cancelled
and u get finally

32T=13500(in K)
i.e.T=148.875 deg.celcius.

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Anirudh Narayanan ·

bhaiya, why did u pink me???? i said i got the wrong answer!!!

11
Anirudh Narayanan ·

"btw" means "by the way"

can u pls post the solution?

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Lokesh Verma ·

it is correct john :)

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JOHNCENA IS BACK ·

is my ans. correct strider,becoz u wrote something like btw in ur reply which confused me.

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Anirudh Narayanan ·

i'll give my solution......

btw, ur ans is perfect, cena