A closed vertical cylinder is divided into two parts by a frictionless piston, each part contains one mole of air. At 27°C, the volume of the upper part is 4 times the volume of the lower part. Calculate the temperature at which the volume of the upper part is 3 times the volume of the lower part..
PLS GIVE COMPLETE SOLUTION AND BEAR WITH MY STUPID DOUBTS
1IF U UNDERSTOOD UR MISTAKE THEN PLEASE REPLY SO THAT I CAN LEAVE THE FORUM.
1it will be far better for me to save time coming to forum and spending hours to check if one has solved them or not.i would better leave the forum and study myself as i used to do earlier.someone told me on goiit that it is good forum where u surely get a nice reply to solve ur queries.......may be i got rong info......i will see if that is so today at 8.
1see i was forced to think like that,i try to help others as i can,so,i also deserve my queries be solved by nishant sir.........don't i.
then i don't think if it is harsh.i will again peep into forum at today 8 pm to check if my queries have been solved,if not,then bye.........
1let me see if i find that behaviour of nishant sir changes(he starts replying to my queries) then i may change my decision.
1strider,
i don't want to hurt u by not replying to ur friendship offer.
but i thing i am being neglected by nishant sir and this forum(few people on forum of course not u) don't need me on the forum.so i think i should leave the forum for ever.ya...but if i chose to remain i will surely love to have a friend like u.
1oh ur reply came while i was typing.
btw...i got it right by using the best god gift-brain.
11I KNOW WHERE I WENT WRONG
BUT I DUNNO HOW U GOT IT RIGHT...
1ARE YAAR LAGTA HAI KAL JAISIE AKSHAY KE KARAN SHAAM GAYI VAISE HI AAJ BHI JAYEGI..
OK...LEAVE IT.
NOW
U WILL GET FINAL ANS. WHEN U PUT C AND Cf VALUES IN IT.
I SAY C AND Cf ARE DIFF.......UNDERSTOOD.(DIFF. TEMP)
U DON'T KNOW C ,U DON'T KNOW Cf
SO IN YOUR FINAL EQUATION U CAN'T PUT THEIR VALUES.
SO U CAN'T GET THE ANSWER.U DID NOT CONSIDER THESE CONSTANT AND SO GOT THE ANSWER(WRONG) BY WRONG METHOD.........I THINK NOW U UNDERSTOOD HOW I ACCOUNT FOR THIS.
1OK
SEE IN UR SOLU. U URSELF SAID THAT
P IS INV. PROP. TO V...RIGHT
SO,NOW THERE IS A CONSTANT C ALSO INVOLVED IN P VALUE....OK.
IN LATER CASE (UPPER VOL. 3TIMES CASE) THERE ALSO A CONSTANT Cf INVOLVED. Cf IS DIFF. FROM C AS IN TWO CASE TEMP. IS DIFFFERENT.
YOU DID NOT CONSIDER THIS IN UR SOLU. THAT'S WHY WRONG ANS.
1friend maybe u got pink as it was in ur luck.oh anyways it doesn't make any difference to me. cheers!!!!!!!!!!!!!!!
BEST OF LUCK
FOR UR PREPARATION.
1of course,at first i did not post the solution as there wud hav been no point in posting wrong solution if my ans. was wrong.
method-
first calculate initial pressure of upper and lower parts.A be area of cross section of piston.
then,we have
P(low)A=P(up)A+mg
calculate mg.
then calculate final pressure of upper and lower parts.
then,
Pf(low)A=Pf(up)A+mg
all variables except temp. will get cancelled
and u get finally
32T=13500(in K)
i.e.T=148.875 deg.celcius.
11bhaiya, why did u pink me???? i said i got the wrong answer!!!
11"btw" means "by the way"
and ur answer is perfrct
can u pls post the solution?
1is my ans. correct strider,becoz u wrote something like btw in ur reply which confused me.
