11Q2
molarity = 0.00351
molality = 0.0091
1.Calculate the vapor pressure of 0.1M aqueous solution of non-electrolytes at 75°C.
2. Calculate the molality and molarity of a solution made by mixing equal volumes of 30% by weight of sulphuric acid(density = 1.2 gm/ml)and 70% by weight of sulphuric acid(density=1.60 gm/ml).
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4 Answers
11Q1 there are many things missing which must be given in the question
it must be mentioned if the solutes are volatile or non volatile also density of water at 75°C must be given
let density of water given at this temp = d
also molar mass of solute is also necessary
for non volatile solutes:
vapour pressure of solution= p°x1
p°= original vp of solvent(water here)
x1= mf of solvent
now p° value for water at ntp/stp(25°C) is about 0.0263atm
using the formula:
ln(p2p1)=
Hv2.303R(T2-T1T2T1)
we can find vapour pressure of water at 75°C if we know the heat of vapourisation Hv of water
for calculating mf--> x1
molar mass of solute is required
11i think in the first ques she wanted to ask lowering of vapour pressure but evven then im confused....
