a gas

1 mole of a gas xpands with temperature T such dat its volume V=kT2 where k is a constant if d temperature of d gas changs by 60° den find d work done by d gas ?

a gas has molar heat capacity C=37.35Jmol^-1 K^-1 in d process PT=k find d no of degrees of freedom of d molecules in d gas

9 Answers

11
virang1 Jhaveri ·

ΔV = k(t2 + 3600 - 120T)

W = pΔV
W =pk(t2 + 3600 - 120T)

W is the work done by the gas

1
brinda laxmi ·

ans is 120R

1
ANKIT GOYAL ·

V=KT2
T/P=KT2
P=R/(KT)
W=∫P.dv
dv=2TK
W=∫1/(KT)2KTdT
W=2*(T2-T)
W=2*60R
W=120R

1
ANKIT GOYAL ·

is this ok
Thanks for revising mine concepts

21
tapanmast Vora ·

hey ram :

W=2*(T2-T)
W=2*60R

Wer did R cum frm?? [7]

1
~AjInKyA~ ·

ya 120 * R IS correct

21
tapanmast Vora ·

that to is crrct only,

i wanna know in ram's methd wer ddid R cum frm?

1
~AjInKyA~ ·

INSTEAD OF nRdeltaT
HE FORGOT WRITIN R in one step
but in final he didnt !

W=2*(T2-T)R
W=2*60R

21
tapanmast Vora ·

oh okay....

got wer he missd out "nR"

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