24Intensity=1400 =Power/Area =σAsunTsun4/4πRearth4
(becoz e=1 for black body)...........fill the values and u will get the ans
The surface of earth receives solar radiations at the rate of 1400 W/m2 The distance of the centre of the sun from the surface of the earth is 1.5 x 1011m and the radius of the sun is 7 x 108m Treating sun as a black body It follows from the above data that the surface temperature of sun is about
Please give the method to solve the ques
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24
3intensity at earth is 1400
TRETIN IT AS A POINT OBJECT ......
I0/4Î d2 = 1400 d is distance between earth and sun....................
I0 = 1* 4Î R2*T4
must hav gone terribly rong
3and eureka R(EARTH ) is not given nor is that wierd angle given to cal. it!!!!!!!!!!!!!!!!!
and in mah ans. R is radius of sun....sorry i forgot to mention it!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
24why would u need angle?????????
we need distance of earth from sun...........and by R earth i meant that a sphere drawn taking sun as centre and earth on its surface.......so intensity will be same on each pt...............i am 1000% correct in my approach.....[1]
3ohhhh!!! i thought that was radius of earth which was not given!!!!