yes ur right its isobaric cos itll adjust itself to atm P
1. U = Q- W
dU/dt = dQ/dt - dW/dt
use dQ/dt = kA/t ΔT dW/dt = nRdT/dt U =3/2 nRT →dU/dt =(3/2)nRdT/dt
ull get (3/5)dQ/dt as ans =6kA/5t
2. similarly use abv eq to get
5/2 nRdT/dt = kA/t ΔT integrate and solve to get 5nR/2kA ln9/8