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I didnt understand ur ques..On PV graph..there is no straight line passing through oriigin of any process,,
we have isochoric on PT and isobaric on VT
1Hi Eureka....in question it is given that PV graph is a straight line passing through origin....
Hence it is a problem with assumption....don't relate it with theory....
Now to the question...
SInce there is straight line on PV curve hence relation in PV will be..
P = m.V
Now we know that PV = nRT
so m.V^2 = n.RT------(1)
...
also work done or energy = ∫p.dv = ∫m.V.dV= mV^2/2
I.e now energy = 1/2*m.V^2 = nRT/2 {from 1}
Now Molar specific heat = energy /n.T
Molar specific heat = nRT/2.n.T = R/2
Hence second option is correct.
Now for second question.....please clearify what is Cc?
1n this question p=mv thereofre pv^-1=m a constant c=cv+r/1-x
and here x=-1 therote the anser should be 3/2r
3molar specific heat capacity =1/nΔQ/ΔT
and not workdone/dT
3abt the molar heat cap for first question
frm process we get ..... P=kV ....
nCdT =nCvdT + PdV ...FIRST LAW OF TD[dont rem. number [3] it think first only hehe]
rearrangin
C = Cv + P/n dV/dT
also
PV=nRT ,,
or kV^2 = nRT
or dV/dT = nR/2kV ,,,,
or nR/2P
C = Cv + R/2 ..
find Cv for monoatomic .. and find C......
and varun mem. formulas like the 1 u stated is harmful for health!!!!![3]
3
iitimcomin
·2009-11-08 07:00:21
question B
assumin by Cc u mean Cv !!!!! [3]
we only need dV/dT >0 [refer prev post!!!]
P^aV^b= c ..
or kV/V^(b/a) = nRT
k V(1-b/a) = nRT ..
clearly ... if 1-b/a > 0 dV/dT>0
or b>a
so option 2,3,4 are right ....
1
shikher mishra
·2009-11-08 08:03:30
to convert a real gas to a ideal gas the conditions favorable are
a:high temperature low pressure