# Recently Active Trignometry Questions

• If cosecA+secA=cosecB+secB,prove that tanAtanB= cot(A+B)/2 . ...
replied2010-07-27 05:47:11
• If tan Î¸/2 = âˆš1-e/âˆš1+e tan Î±/2 ,then cos Î±=? Plz show the steps also along with the solution.... ...
replied2010-07-27 05:04:38
• What is the sum of the roots of the equation (x+1) = 2log2(2x + 3) - 2log4(1980 - 2-x)?? ...
replied2010-07-25 06:46:01
• What is the value of (1+cos Ï€/9 )(1+cos 3Ï€/9 )(1+cos 5Ï€/9 )(1+cos 7Ï€/9 ) ...
replied2010-07-24 10:54:45
• Î£ cot-12n2 nâ†’âˆž ...
replied2010-07-24 01:56:57
• if Î±, Î², Î³ are connected by the relation 2 tan2Î± tan2Î² tan2Î³ + tan2Î± tan2Î² + tan2Î² tan2Î³ +tan2Î³ tan2Î± =1, then the value of cos2Î± +cos2Î² +cos2Î³ is ________ answer: 1 ...
replied2010-07-16 10:38:47
• tanÎ¸+tan(Î¸+60)+tan(Î¸-60)=k tan 3Î¸,where k is equal to: a)1 b)2 c)3 d)4 ...
replied2010-07-14 23:37:19
• Let Î¸[0,45] and t1=tanÎ¸tanÎ¸, t2=tanÎ¸cotÎ¸, t3=cotÎ¸tanÎ¸, t4=cotÎ¸cotÎ¸, then: a)t1>t2>t3>t4 b)t4>t3>t1>t2 c)t3>t1>t2>t4 d)t2>t3>t1>t4 ...
replied2010-07-14 09:57:53
• 1.Prove that sin(3x) = 4sinx.sin2x.sin4x 2.Solve : cosx(1+sin x/4 - 2cosx) + sinx (cosx/4 - 2sinx) = 0 3.solve : cos 3x + cos 2x = sin 3x/2 + sin x/2 , x=(0,pi) 4.solve for x and y : cos2x + cosx.cosy + cos2y = 0 ...
replied2010-07-13 20:39:07
• What is the minimum value of 9sec2x + 10cosec2x for all x belongs to R?? ...
replied2010-07-13 10:10:15
• Prove: sinx/cos3x + sin3x/cos9x + sin9x/cos27x = 1/2 (tan27x-tanx) ...
replied2010-07-13 09:52:14
• If cos Ï€/7 , cos 3Ï€/7 , cos 4Ï€/7 are the roots of the equation 8x3-4x2-4x+1 = 0 then the What are the values of expressions sin Ï€/14 sin 3Ï€/14 sin 5Ï€/14 and cos Ï€/14 cos 3Ï€/14 cos 5Ï€/14 ???? ...
replied2010-07-13 02:44:57
• in any triangle ABC, the value of \sum{} a(b2+c2) cosA is 1) 3 abc 2)3(a2+b2+c2) 3)a2+b2+c2 4)abc answer: 1)3 abc ...
replied2010-07-09 07:46:01
• IF K1 = tan 27Î¸ - tan Î¸ and K2 = sin Î¸/cos 3Î¸ + sin 3Î¸/cos 9Î¸ + sin 9Î¸/cos 27Î¸ , then 1. K1 = 2K2 2. K1 = K2 + 4 3. K1 = K2 4. none of these ...
replied2010-07-08 15:54:25
• Prove that :- \sum_{r=1}^{n}{tan\ r\ \alpha }\ .\ tan\ (r+1)\ \alpha = cot\ \alpha \ . \ tan\ (n+1)\ \alpha\ - n - 1 ...
replied2010-07-08 05:11:54
• please tell me any good online book for trignometry ...
replied2010-07-07 08:57:02
• 1.If A+B+C = âˆ and A,B,C belongs to (0,âˆ/2) then prove that secA +secB +secCâ‰¥6 2.Prove that sinx.sin2x.sin3x <9/16 3.Prove that in triangle Î”ABC cosec A/2 + cosec B/2 +cosec C/2 â‰¥ 6 4.Prove that in triangle Î”ABC ...
replied2010-07-07 03:56:58
• 1.prove that sinx.siny.sin(x-y) + siny.sinz.sin(y-z) + sinz.sinx.sin(z-x) + sin(x-y).sin(y-z).sin(z-x) = 0 2.f(Î±,Î²)= cos4Î±/cos2Î² + sin4Î±/sin2Î² then prove that f(Î±,Î²) = 1 3.cosA = tanB, cosB = tanC and cosC= tanA then ...
replied2010-07-06 21:03:38
• help me out on these ones.... 1)The perimeter of the sector of a cricle is equal to the circumference of the semi circle of the same radius.Find in circular measure the angle subtended at the centre by bounding radii of the s ...
replied2010-07-06 20:40:18
• help me out on these ones.... 1) The greastest angle of a cyclic quadilateral is three times the least angle and the other two angles are in ratio 4:5.Find the angles in circular measure? 2)If the circumference of circle be d ...
replied2010-07-06 11:23:32
• 1.Prove that sin2nx + cos2nx â‰¤ 1 for all x and nâ‰¥1 ...
replied2010-07-06 04:00:07
• 2.A + B + C = 180 prove that cos A/2 + cos B/2 + cos C/2 = 4cos(âˆ-A)/4 . cos(âˆ-B)/4 . cos(âˆ-C)/4 ...
replied2010-07-04 01:37:12
• Prove that sin 27Â°=1/4(âˆš3+âˆš5-âˆš3-âˆš5) ...
replied2010-07-03 09:18:01
• If cos(Î±-- 3Î¸) cos3Î¸ =sin(Î±-- 3Î¸) sin3Î¸ =m prove that cos Î±=2--m^2 m. TRIGNOMETRY ...
replied2010-07-03 08:56:41
• If m tan(Î¸-30)=n tan(Î¸+120), then m+n/2(m-n) is equal to: a)tan2Î¸ b)cos2Î¸ c)sin2Î¸ d)cot2Î¸ ...
replied2010-07-02 07:08:02
• Find the value of: \sqrt 3 \csc 20^{\circ} - \sec 20^{\circ} ...
replied2010-07-01 04:55:39
• cosÎ±+cos2Î±+p , sinÎ±+sin2Î±=q then eliminate Î± ...
replied2010-06-28 05:14:00
• sinÎ¸+cosÏ†=1/âˆš2 and cosÎ¸+sinÏ†=âˆš2/3 then find the value of sin(Î¸+Ï†) and tan (Î¸-Ï†)/2 ...
replied2010-06-27 08:00:50
• sin9Â°=1/4(âˆš3+âˆš5-âˆš5-âˆš5) ...
replied2010-06-27 07:17:48
• eliminate Î¸ from atanÎ¸ +bcot2Î¸ = c acotÎ¸ - btan2Î¸ = c ...
replied2010-06-27 06:28:44