find the value of the expression

in any triangle ABC, the value of \sum{} a(b2+c2) cosA is

1) 3 abc 2)3(a2+b2+c2)
3)a2+b2+c2 4)abc

answer: 1)3 abc

3 Answers

62
Lokesh Verma ·

rearrange to get Σab(b cos A+ a cos B)=Σabc=3abc

39
Dr.House ·

simple jee way of doing this is

if u put a=b=c

u find all 4 options in answer come out different

so substitute that and u r there at your answer

62
Lokesh Verma ·

for a 50-50 lifeline you could even say that options 2 and 3 are wrong dimensionally :)

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