Trigo probems

help me out on these ones....

1) The greastest angle of a cyclic quadilateral is three times the least angle and the other two angles are in ratio 4:5.Find the angles in circular measure?

2)If the circumference of circle be divided into five parts which are in A.P. and if the greatest part be six times the least.Find in radians the angle subtended by parts at the centre?

give descriptions....

2 Answers

62
Lokesh Verma ·

x, 3x, 4y, 5y

Greatest + least = 180 so x=45

also 9y=180

angles are 45, 80, 100, 135

62
Lokesh Verma ·

a, 6a be the two parts...

so total sum = (6a+a)/2 x 5 = 2 pi

a=4 pi /35 radians

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