replace all vowels by x ..
so new word is
VxNxS
no.of ways of permutation is 5!2!
how many ways can the word VENUS be arranged so that the vowels do not change thein orders??
lets assume cases here:
1)E _ _ _ _
in dis case other four can be arranged in 4!=24 ways..
2)_ E _ _ _
in dis case the first letter has 3 options(cant be U),3rd letter has 3 options,4th has 2 options nd de last 1ne has 1 option
total no of ways=3*3*2*1=18 ways
3) _ _ E _ _
in dis case de first letter has 3 options nd 2nd and 4th letter has 2 options nd de last 1ne has 1 option
no of ways = 3*2*2*1=12
4)_ _ _ E _
in dis case de last letter has to be u nd first three can be arranged in 3! ways.....=6 ways....
the last letter cant be E
total ways=24+18+12+6=60
actually another gud way of thinking dis is either de order will be E before U or E after U
so total ways will be 5!2 for each case....
replace all vowels by x ..
so new word is
VxNxS
no.of ways of permutation is 5!2!
to mantain the correct order "u" must come after "e"
So when e in frst place the rest can re arrange in 4! ways.
when in 2nd place frst place can be filld in 3 ways nd in each case d rest can re arrange in 3! ways. i.e 3*3!=18 ways..
similarly when in nxt place they cn arrange in 3p2 i.e 3! ways multiplied by 2 ways i.e 12 ways.
similarly in nxt case they ca rearrange in 3! ways
total no of ways =24+18+12+6= 60 ways