2305
Shaswata Roy
·2013-03-05 00:53:43
@Soumyabrata Mondal
Even I had thought of that before.
But you see,
\dpi{200} \fn_cs e^{i\pi} = -1\Rightarrow log(-1) = i\pi
Hence log(-1) does have a value.
229
Dwijaraj Paul Chowdhury
·2013-03-05 05:38:21
For 1st one.....
The first question was given in ISI
you cant express two negative nos which are in square root
form as two different roots...i mean√(-1*-1) cannot be written as root-1 *root -1...nd @Roy the question is --"Proof that"?? :-|
1357
Manish Shankar
·2013-03-11 00:03:36
√a/b=√a/√b for positive values of a and b only
229
Dwijaraj Paul Chowdhury
·2013-03-12 07:29:02
for the 1st proof
Dekh log er value replace korle
3i*pi=1i*pi
Now LHS=(0,3*pi)
And RHS=(0,pi) by multiplication of complex nos. But as they don't represent the same complex nos. on an argand plane, they cannot be equal. :. Contradiction. LHS is not equal to RHS.
337
Sayan Sinha
·2013-03-12 23:53:12
I think, for the 2nd one,
log is not possible for a negative number.