If
|z|2 + A(bar) z2 + A z(bar)2 + B(bar) z + B z(bar) + c=0
represents a pair of straight lines intersecting with angle θ, then the value of |A| is-
a) tanθ
b) cosθ
c) secθ
d) secθ/2
Sorry for the inconvenience, the latex is not working.
106\left| z\right|^2 + A\bar{z}^2 + \bar{A}z^2 + B\bar{z} + \bar{B}z + c=0
latexing
1Let z=reiθ
A=raeiα
B=rbeiβ
Dividing through out the gven eqn by |z|2
+C+1=0
latex is turning out to be very difficult
This wen simplified using the above values and trignometry gives.........
2(racosα+rbrcosβ)eiθ+c+1=0
But finally............... what does this represent!!![5][5][5]???[7][7][7]
1[1]
I too reached somewhere about nearby...though less complex :P
1r u sure this is from reso rank booster
i din find it anywer der ?
is it in rank refiner one ?
and r u sure u r not missing something in the question.
1@ to those ones...
This is actuallu a question from MQB from there package and given in some refiner or master or something..
