Let A and B be te two numbers
G2 = AB
now, A,p,q,B are in A.P
common difference = B-A/3
=> p= A + B-A/3 = 2A+B/3
and q = A + 2(B-A)/3 = 2B+A/3
now (2p-q)(2q-p)= AB putting values of p and q
thus AB= G2 = (2p-q)(2q-p)
Hence proved
Ques1) If one Geometric mean G and two arithmetic means p & q are inserted between two quantities, then show that
G2 = (2p-q)(2q-p)
Ques2) Let a,b,c are respectively the sum of the first n terms, the next n terms, and the next n terms of a G.P. Show that a,b,c are in G.P.
Let A and B be te two numbers
G2 = AB
now, A,p,q,B are in A.P
common difference = B-A/3
=> p= A + B-A/3 = 2A+B/3
and q = A + 2(B-A)/3 = 2B+A/3
now (2p-q)(2q-p)= AB putting values of p and q
thus AB= G2 = (2p-q)(2q-p)
Hence proved