62
Lokesh Verma
·2010-06-10 20:39:44
1st one is very simple..
it is given that 2R+θR=P
maximize θ/2 R2
SO same as maximizing (P-2R)R.2
Now solve
1
Euclid
·2010-06-10 20:41:48
yes bhaiya.... ans comes out 2 be P/4.....mine too.... bt its given p/2!!!!
1
Euclid
·2010-06-12 00:46:18
1) Which of these are infinitely large??
a) y=2x sin-1(sinx) as x-->+∞
b) y=(2+sinx)logx as x-->+∞
c) y=(1+sinx) logx as x-->+∞
2) Prove that if the limit of the function f(x) is equal to 'a' as x-->∞, then f(x) is representable as sum f(x) = a+g(x), where g(x) is is an infinitesimal as x-->∞.
3)The function un takes on the following values
u1=1/4; u2=1/4 + 1/10;...... un=1/(3+1) + 1/(32+1) +.......+ 1/(3n+1)....
Prove that un tends to a certain limit as n-->∞
4) Prove the theorem - if the difference between two functions for one and the same variation of the independent variable is an infinitesimal, one of them increasing, the other decreasing at the same time, then both the functions tend to one and the same limit.
5) How many points of discontinuity (and of what kind) has the function y=1/log!x! ?? (!x!=mod x)
23
qwerty
·2010-06-12 01:34:08
euclid , for 2nd i m not sure if it is correct
consider f(x) - g(x) .
Let this be equal to some k
so f(x) = g(x) + k
so g(x) = f(x) - k
now lim g(x) = 0
x->∞
so lim [ f(x) - k ] = 0
x->∞
so lim f(x) = k
x-> ∞
hence a = k
1
Euclid
·2010-06-13 00:16:48
but qwerty hw did u get lim(x-->∞) g(x)=0 ??
that means the question is true for any tending value of x???
1
Euclid
·2010-06-13 00:41:11
but c nt given to be infinitely large
106
Asish Mahapatra
·2010-06-13 02:31:38
oops yes.. i din see that it was 1+sinx
as sinx can be anything between -1 and 1, for x-->∞, sinx can be -1 also so, 1+sinx = 0 (exact) (for some values of x)
so its only (b) as 2+sinx can never be equal to zero
similarly it wont be (a) cuz sin-1(sinx) can be zero also
23
qwerty
·2010-06-24 23:41:34
euclid is it given na that as x tends to infinity g(x) tends to zero