1ayush i too got the same answer but via graphs
Let f(x)=x (| x- π|) (2 + cos2x), x∈R. Then the function f: R→R is
A) one - one but not onto
B) onto but not one one
C) both one-one and onto
D) neither one one nor onto
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3 Answers
1I think answer shud be B)
f(0) = f(∩) = 0 hence not a one one function
further range of 2 + cos2x is (2,3) and that of the other function is R
Range of the other function can be calculated by considering two cases
CASE 1- x<∩
CASE 2- x>∩
Since either case 1 OR case 2 is possible we use union in combining the ranges