Find a 7 digit number which has its own address...
i.e.
see this 4 digit number(not the number required) ex 1210
here 1 should say it has total 1 zero in the number
2 in second place say it has 2 one in the number .
1 in third pace says it has 1 two in the number
and 0 in 4 place says it has zero 3 in the number.
and so on...
Try for 5,6,7,8 digit number...
1for 5→21200
for 6→_ _ _ _ _ _
for 7→3211000
for 8→42101000
for 9→521001000
for 10→6210001000
for 11.................................
sorry i am editing my ans for six digit and i think no addresing no exist for six digit
if i am mistaken plz help me to correct it
1hey priyam i think you solved this using programming first
??
is that so ??
if it is im going to wrtie one to solve this and tell you ans later
33yes if u get any 1 of them u get the pattern and can do all
[1]
1you can use a constraint eq in the question that sum of numbers i equals to number of digits given