root 2 = 2

There is a square of side 1.
remove a square from the vertex

keep repeating till you get a pattern like in the image....

now if you move from one vertex of the square to the opposite one, then the length traversed is always 2...

But in the limiting case.. when you tend to infinity, the length traversed is âˆš2

Hence 2= âˆš2

What is the flaw?

6 Answers

same old trick :P

lets see if anyone can guess !!!

any hint

Wow someone has dug out an old thread..

This is interesting... It in one way explains the relevance of limits ;) :P

nishant bhaiya....please post the solution!!!

???

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∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

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° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω