1areyy, this is a really simple question!
I wonder no1 has given any solution to it! :P
If AB = a, AD = b, AC = 2b+ 3c & the area of quadrialteral ABCD is β times the area of ||gm whose adjacent sides are a, b. find the value of β.
Here, a represents vector a, AC represents vector AC.
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8 Answers
11is the ans. 1/2 + 3/2(bxc/axb)
b c a are vectors and its is the cross product of b and c divided by the cross product of a and b
1@Amritansh--ya i made a silly mistake......the vector AC = 2a + 3b.
Now, can u solve it?
1357Check one again Amritansh
How can be the area of quadrilateral less than the area of parallelogram
11/2[a x(2a + 3b)] +1/2[(2a + 3b) x b]
=1/2[3a+b x(2a + b)]
=5/2 (a x b)
comparing β=5/2