13thanq [1]
Def : {a} = min (a-[a] , [a]+1-a)
'{a}' can be defined as the distance of 'a' to the nearest integer on number line...
6n-1
Find Σ min ({r/3n} , {r/6n})
r=1
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17 Answers
62maq solve this one.. dude... i think it is a good question..
if u dont i will put it as the QOD ;)
9as nishant sir said div exp into 2 exp , for 2nd exp put r=6n -r to make it similar to ist exp
so ans is 2 (Σ 1 to 3n min of those tings )
= 2 ( Σ1 to 2n r/6n + Σ 2n+1 to 3n 1 - r/3n )
simplify
13hmmm... may be... me too didn't write it completely on paper...
juzz wrote 2-3 initiation steps... n then closed my buk n went to drink water... [6] [4]
62oh it is not too lengthy...
Not vulgarly lengthy i mean...
But then i havent written it on pen and paper.. so cant say :)
13don't make an impression dat i couldn't solve it... make an impression dat i didn't solve it... [3] [4]
13nope bro... i didn't solve it... juzz because it seemed too lengthy at first site... so i left it... [2]
well, make it d question of d day... i'm more interested in watching how others solve such questions rather than solving it myself... [6]
plzz make it QOD... [1]
62'
hint :
when r=3n/2 then
take the limits like r=1 to 3n
3n+1 to 6n-1
11Everyone's too dazed to reply. Let them recover from their stupor first [1]
