Arithemetic Progression

What is the sum of all 3 digit numbers that leave a remainder of '2' when divided by 3?

2 Answers

262
Aditya Bhutra ·

the AP will be - 101 , 104, 107, ...... 998
common diff. = 3
first term=101
last term = 998
no. of terms = 300
total sum = 300/2 * (101 +998 ) =164580

1
Vatsalya Goel ·

thnx

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