by pythagoras theorem
r2+r2=(r+(√2+1))2
by solving this and rejecting the negative root
we get
r=3+2√2
c1 is a circle of radius 1 touching the x axis and the y axis. c2 is another circle of radius > 1 and touching the axes as well as the circle c1. then the radius of c2 is
by pythagoras theorem
r2+r2=(r+(√2+1))2
by solving this and rejecting the negative root
we get
r=3+2√2