Complex numbers-tough

If A(z1),B(z2),C(z3) are the vertices of an equilateral triangle in the argand plane,then is _____

11 Answers

1
dimensions (dimentime) ·

is the ans -pi/3

1
krish1092 ·

@Dimensions,
The answer is not -pi/3

1
dimensions (dimentime) ·

pi/2??????????/

1
krish1092 ·

@Dimensions,
Please post the solution as its the correct answer!!!

1
dimensions (dimentime) ·

sorry for the previous, calculation mistake,

ok, just assume 1,ω,ω2as z1,z2,z3, as they are one of the 3 pairs of vertices of triangle..........

now solve further,.......

it's a good trick for objectives only

& one more thing, the latex is not working,

it cannot be saved as JPEG,

it is saving as GIF.

what to do.?????????/

62
Lokesh Verma ·

umm.. there is a very slight mistake.. dimesnions...

you dont know that the origin is the center!!

You have also used rotation..

the vertices will be

Z1= Z0+r.eiθ
Z2= Z0+r.ei(θ+2pi/3) = Z0+r.eiθω
Z3= Z0+r.ei(θ+4pi/3) = Z0+r.eiθω2

This will be the moregenral proof!

1
dimensions (dimentime) ·

arey aayega na,

u will get
arg(constant*i)
which is pi/2

1
dimensions (dimentime) ·

& i have already mentioned, that it is good for objectives only............

62
Lokesh Verma ·

Yup dimension.. the point that u make is agreed to ....

Sorry din read that part :)

341
Hari Shankar ·

Use of geometry will simplfiy things greatly

z2+z3-2z1 =(z2-z1)+(z3-z1).

You can see that this is the angular biesctor of z2-z1 and z3-z1 and this will be perpendicular to the third side namely z2-z3

Hence the required argument is 900

62
Lokesh Verma ·

Prophet.. i was thinking of posting this one ;)

But i just stopped short..

Good that you observed it :)

Gr8 work .....

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